On Equations for determining cosπ/ (2n+1)
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Authors
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K. J. Sanjana
DOI:
https://doi.org/10.18311/jims/1911/17816Abstract
Taking the equation cos2nθ + cosθ = 0, we have cos 2nθ=cos(Ï€-θ), So that 2nθ=(2r*#177;1)Ï€±Î¸.
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Published
1911-04-01
How to Cite
Sanjana, K. J. (1911). On Equations for determining cosπ/ (2n+1). The Journal of the Indian Mathematical Society, 3(2), 72–74. https://doi.org/10.18311/jims/1911/17816
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Copyright (c) 1911 K. J. Sanjana
This work is licensed under a Creative Commons Attribution 4.0 International License.
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